Res342 E-Text+Wk1

E-Text RES/342 Chapter 8, fare 8.48 A sample of 20 pages was understand without replacement from the 1,591-page ph 1 directory Ameritech Pages Plus Yellow Pages. On to all(prenominal) one page, the mean area devoted to ostentation ads was mensural (a display ad is a large block of colored illustrations, maps, and text). The information (in square millimeters) are shown below: 0 260 356 403 536 0 268 369 428 536 268 396 469 536 162 338 403 536 536 130 (a) prepare a 95 portion self-assertion separation for the current mean. (b) wherefore might normality be an issue present? (c) What sample size would be demand to obtain an fallacy of 10 square millimeters with 99 percent combine? (d) If this is non a reasonable requirement, suggest one that is. (Data are from a project by MBA student Daniel R. Dalach.) A) x-bar = 346.5 - flirt with s=170.378 Standard deviation T-critic al care for for 95% CI with df =19= 2.093 E= 2.093 * 170.378/sqrt (20)=2.0931.96 * 38.0976 = 79.74 95% CI: (346.5 79.74, 346.5 + 79.74) = 426.240 upper confidence limit = 366.760 lower confidence limit B) A CI statement is about the whole population. This random sample is in all probability not the whole population.

C) n = (t * s / E) n = (2.576*170.378/10)^2 = 1926.067 n = 1927 D) Increase E or decrease the confidence level Chapter 8, Exercis e 8.64 Biting an unpopped union of popcorn! hurts! As an experiment, a self-confessed(prenominal) connoisseur of cheap popcorn care luxurianty counted 773 kernels and put them in a popper. After popping, the unpopped kernels were counted. there were 86. (a) Construct a 90 percent confidence interval for the proportion of all kernels that would not pop. (b) Check the normality assumption. (c) pick up the Very Quick Rule. Does it draw well here? Why, or why not? (d) Why might this sample not be typical? A) E = z * (p-hat/sqrt (n)) E =...If you sine qua non to get a full essay, order it on our website: OrderCustomPaper.com

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